Electric Field Calculator

Compute electric field magnitude for a point charge, between parallel plates, or from the force on a charge, with unit-aware inputs and step-by-step solutions.

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Topic · Electric Field

Electric Field Calculator – formulas, intuition, and worked examples

Learn what an electric field is, how it relates to charge, distance, voltage, and force, and how to use the Electric Field Calculator above to quickly compute field strength for point charges, parallel plates, and uniform fields acting on a test charge.

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How to use the Electric Field Calculator step by step

The Electric Field Calculator is built to quickly compute field magnitude in three of the most common situations: a single point charge, a uniform field between parallel plates, and a uniform field inferred from the force on a test charge. All three use the same underlying idea – the electric field \(E\) is how strongly charges are pushed in space – but the inputs and formulas differ slightly.

In every mode, the calculator takes care of unit conversions and constants (like Coulomb’s constant \(k\) or the permittivity of free space \(\varepsilon_0\)). You only need to choose the right mode, enter realistic values, and pick the output units you prefer (N/C or V/m and their scaled variants).

  1. 1

    Select the calculation mode. Use the Calculation Mode dropdown to choose one of: Point Charge (E from Q and r), Parallel Plates (E from V and d), or Uniform Field (E from F and q). This tells the calculator which formula to use.

  2. 2

    Enter the known quantities with their units. For a point charge, specify the source charge \(Q\) and distance \(r\). For parallel plates, enter the voltage difference \(V\) and plate separation \(d\). For a uniform field from force, enter force \(F\) and test charge \(q\). You can use convenient units like μC, nC, kV, cm, or mm – the calculator converts everything internally to SI.

  3. 3

    Choose result units and calculate. Use the Result units dropdown to decide whether you want the answer in newtons per coulomb (N/C), volts per meter (V/m), or their kilo-scaled versions. Then press the calculate button (or the main solve action) to compute \(E\). The result card will show the field magnitude and the selected unit.

  4. 4

    Review the equation banner and (if enabled) solution steps. The dynamic equation box above the form shows which formula the calculator used for your current mode, along with a short explanation. If step-by-step solutions are enabled on your page, you can open them to see the numeric substitution and intermediate values, which is helpful for learning and debugging designs.

Diagram showing a point charge producing radial electric field lines and a pair of parallel plates with uniform electric field between them.
Conceptual view of a point charge (radial field) and parallel plates (uniform field) – the three calculator modes are based on these standard textbook cases.

Electric field basics: force per unit charge

At its core, the electric field describes how strongly a charged particle would be pushed at a given point in space. Formally, the electric field \(\vec{E}\) at a point is defined as the force per unit positive test charge:

\[ \vec{E} = \frac{\vec{F}}{q} \]

Here, \(\vec{F}\) is the electric force acting on a small test charge \(q\) placed at the point of interest. The field is a vector quantity, which means it has both magnitude and direction. The Electric Field Calculator focuses on the magnitude of \(E\), because that’s what most homework, lab, and design questions ask for; direction can be inferred from the sign of the charges and the geometry.

Electric field strength is measured in newtons per coulomb (N/C), which is equivalent to volts per meter (V/m). This dual interpretation connects forces (mechanical behavior) with potentials (electrical behavior). When you switch the calculator’s result units between N/C and V/m, you’re just changing how the same physical quantity is expressed, not computing something different.

In real engineering problems, fields can be quite complex – superposition from multiple charges, non-uniform materials, and fringing at edges. The Electric Field Calculator purposely focuses on three canonical situations: a single point charge, a uniform field between plates, and a uniform field measured via force on a test charge. These cover a large percentage of introductory physics and practical quick checks.

  • Electric field is defined as force per unit charge, \(\vec{E} = \vec{F}/q\).
  • It is a vector, but the calculator reports the magnitude \(E = |\vec{E}|\).
  • Units N/C and V/m describe the same physical quantity and are interchangeable.

Core electric field formulas used in the calculator

Each calculator mode uses a standard textbook formula customized for your chosen inputs. Behind the scenes, all computations are performed in SI base units (C, m, N, V) before being converted back to your requested units. This reduces mistakes and makes cross-checking with theory straightforward.

For a single point charge \(Q\), the magnitude of the electric field at a distance \(r\) in vacuum is:

\[ E = k \,\frac{|Q|}{r^2} = \frac{1}{4\pi\varepsilon_0}\,\frac{|Q|}{r^2} \]

Here, \(k \approx 8.988 \times 10^9~\text{N·m}^2/\text{C}^2\) and \(\varepsilon_0 \approx 8.854 \times 10^{-12}~\text{F/m}\). In Point Charge mode, the Electric Field Calculator automatically applies this relation using your entered \(Q\) and \(r\). If you enter \(Q\) in μC and \(r\) in cm, the calculator converts them to coulombs and meters before applying the formula.

Between large, parallel conducting plates with a uniform potential difference \(V\) and separation \(d\), the field in the idealized central region is approximately:

\[ E \approx \frac{V}{d} \]

This is the relationship used in Parallel Plates mode. The calculator assumes you are interested in the magnitude of the uniform field away from edges and fringing, which is how most introductory capacitor and field problems are posed. You specify the voltage difference between the plates and their separation; the calculator returns the corresponding field strength.

Finally, if you know the force experienced by a test charge in a (locally) uniform field, you can solve the definition \(\vec{E} = \vec{F}/q\) for the magnitude:

\[ E = \frac{|F|}{|q|} \]

In Uniform Field (E from F and q) mode, you directly enter the force \(F\) and the test charge \(q\). This is particularly useful in lab contexts, where you may measure a force experimentally and want to infer the field, or when analyzing forces on particles in accelerators, deflection plates, or sensor devices.

As you switch modes in the Electric Field Calculator, the equation banner above the form updates with the corresponding equation and a short plain-language explanation so you can verify that the math matches your expectation for the problem at hand.

Calculation modes, units, and typical input ranges

Choosing appropriate units and realistic input values is just as important as knowing the right formula. The Electric Field Calculator is unit-aware: you can mix and match practical laboratory units without worrying about manual conversions or powers of ten.

In Point Charge mode, typical charge magnitudes are small – often in the microcoulomb (μC) or nanocoulomb (nC) range for lab experiments, and sometimes in the millicoulomb (mC) range for thought experiments. Distances frequently appear in millimeters (mm), centimeters (cm), or meters (m). At short distances from a modest charge, electric fields can become extremely large, so double-check that your inputs are physically realistic.

In Parallel Plates mode, the voltage difference might span from a few volts to several kilovolts (kV), and plate separations typically range from micrometers (in microelectronics) to centimeters or millimeters in lab setups. Because the field magnitude scales as \(V/d\), decreasing the separation by a factor of ten at fixed voltage increases the field by a factor of ten.

In Uniform Field from Force mode, the calculator expects a force magnitude \(F\) and a test charge \(q\). Forces might be in millinewtons (mN) up to newtons (N) or kilonewtons (kN), depending on the scale, while charges again are usually in the μC or nC range. If you measure a very tiny force on a relatively large charge, the implied field may be small; the opposite combination yields large fields.

The Result units dropdown lets you choose between:

  • N/C – Base SI unit, directly from \(E = F/q\).
  • V/m – Equivalent SI unit often used in electromagnetics and RF design.
  • kN/C – Scaled unit for very large fields to keep the numbers readable.
  • kV/m – Common in high-voltage engineering and insulation breakdown discussions.

Internally, the calculator always works in base SI, then converts to your chosen display unit at the end. If your output looks suspiciously tiny or enormous, check two things first: whether you selected the intended units for each input and whether your result units match what you expect.

Design checks, limits, and common electric field pitfalls

While the Electric Field Calculator focuses on clean, idealized formulas, real-world systems always have practical limits. Knowing where approximations break down helps you interpret the numeric results correctly.

For point charges, the formula \(E = k |Q|/r^2\) assumes a true point source and a vacuum (or air at low field strengths). At very small distances, physical charges are not perfectly point-like, and materials around the charge can distort the field. Also, at extreme field strengths, air begins to ionize and break down, so the simple electrostatic picture no longer holds.

For parallel plates, the approximation \(E = V/d\) is valid in the central region when the plate area is large compared to the separation and when edge effects (fringing) are negligible. If the plates are small or the separation is comparable to their size, the actual field distribution becomes non-uniform. The calculator’s result is then best interpreted as an average field in the middle region.

In force-based calculations, the main pitfall is measurement error. Because \(E = F/q\), small uncertainty in either \(F\) or \(q\) can significantly change the inferred field. In experimental setups, make sure your test charge is well characterized and that non-electric forces (like gravity, drag, or mechanical contact) are either negligible or corrected for.

Finally, remember that the calculator returns the magnitude of \(E\). Direction still matters physically: fields point away from positive charges and toward negative charges. Between plates, the field points from the positively charged plate to the negatively charged one. When you use the computed field in further vector calculations, be sure to reintroduce direction based on your geometry.

Electric field worked examples

Let’s walk through a few realistic examples that mirror common textbook and exam questions. You can replicate each scenario in the Electric Field Calculator by choosing the same mode, values, and units.

1

Example 1 – Electric field from a point charge in air

A charge of \(Q = +3.0~\mu\text{C}\) is located in air. What is the magnitude of the electric field at a point \(r = 20~\text{cm}\) away from the charge? Use the Point Charge (E from Q and r) mode in the Electric Field Calculator.

Calculator setup: Mode = Point Charge; \(Q = 3.0~\mu\text{C}\); \(r = 20~\text{cm}\); result units = N/C.

\[ \begin{aligned} Q &= 3.0~\mu\text{C} = 3.0 \times 10^{-6}~\text{C} \\ r &= 20~\text{cm} = 0.20~\text{m} \\ E &= k \frac{|Q|}{r^2} = \left(8.988 \times 10^9~\frac{\text{N·m}^2}{\text{C}^2}\right) \frac{3.0 \times 10^{-6}~\text{C}}{(0.20~\text{m})^2} \\ &= 8.988 \times 10^9 \times \frac{3.0 \times 10^{-6}}{0.040}~\frac{\text{N}}{\text{C}} \\ &\approx 6.7 \times 10^5~\text{N/C} \end{aligned} \]

Result: The electric field magnitude is approximately \(6.7 \times 10^5~\text{N/C}\) at 20 cm from a 3 μC point charge. In the calculator, you should see a value on this order when you use the same inputs and choose N/C as the output unit.

2

Example 2 – Field between charged parallel plates

A pair of parallel plates in a test setup are separated by \(d = 5.0~\text{mm}\) and held at a potential difference of \(V = 2.5~\text{kV}\). Assuming the field between the plates is uniform, what is the electric field magnitude? Use the Parallel Plates (E from V and d) mode.

Calculator setup: Mode = Parallel Plates; \(V = 2.5~\text{kV}\); \(d = 5.0~\text{mm}\); result units = kV/m or V/m.

\[ \begin{aligned} V &= 2.5~\text{kV} = 2.5 \times 10^3~\text{V} \\ d &= 5.0~\text{mm} = 5.0 \times 10^{-3}~\text{m} \\ E &= \frac{V}{d} = \frac{2.5 \times 10^3~\text{V}}{5.0 \times 10^{-3}~\text{m}} \\ &= 5.0 \times 10^5~\text{V/m} \end{aligned} \]

Result: The electric field is \(5.0 \times 10^5~\text{V/m}\), which is also \(500~\text{kV/m}\). In the Electric Field Calculator, selecting kV/m as the output unit will display a value around 500 kV/m.

3

Example 3 – Inferring field from a known force on a charge

A test charge of \(q = -1.2~\mu\text{C}\) experiences a horizontal electric force of magnitude \(F = 0.030~\text{N}\) in a uniform field region. What is the electric field magnitude? Use the Uniform Field (E from F and q) mode.

Calculator setup: Mode = Uniform Field (E from F and q); \(F = 0.030~\text{N}\); \(q = 1.2~\mu\text{C}\) (use the magnitude); result units = N/C.

\[ \begin{aligned} F &= 0.030~\text{N} \\ q &= 1.2~\mu\text{C} = 1.2 \times 10^{-6}~\text{C} \\ E &= \frac{|F|}{|q|} = \frac{0.030~\text{N}}{1.2 \times 10^{-6}~\text{C}} \\ &= 2.5 \times 10^{4}~\text{N/C} \end{aligned} \]

Result: The electric field magnitude is \(2.5 \times 10^{4}~\text{N/C}\). The negative sign on the original test charge only affects the direction of the force relative to the field, not the magnitude computed by the calculator.

Illustration of example electric field setups including a point charge, parallel capacitor plates, and a charged particle experiencing a force in a uniform electric field.
Example configurations that match the three calculator modes: point charge, parallel plates, and a charged particle in a uniform field.

Electric field & Electric Field Calculator – frequently asked questions

What is an electric field in simple terms?

In simple terms, an electric field describes how strongly electric charges would be pushed at a particular point in space. If you placed a tiny positive test charge at that point, the electric field tells you what force it would feel per unit charge. The Electric Field Calculator uses standard formulas to quantify that strength in units like N/C or V/m.

How do I calculate electric field from a point charge?

For a single point charge in air or vacuum, the magnitude of the electric field at distance \(r\) is \(E = k |Q| / r^2\), where \(Q\) is the charge, \(r\) is the distance, and \(k \approx 8.988 \times 10^9~\text{N·m}^2/\text{C}^2\). In the Electric Field Calculator, select Point Charge (E from Q and r), enter \(Q\) with its units (C, mC, μC, nC), enter \(r\) with its units (m, cm, mm, km), choose the output unit, and compute.

How do I find the electric field between parallel plates?

For large, closely spaced plates with a potential difference \(V\) and separation \(d\), the central region of the field is approximately uniform and given by \(E \approx V/d\). To use the Electric Field Calculator, choose Parallel Plates (E from V and d), enter the voltage (V or kV) and separation (m, cm, or mm), and select N/C or V/m as the output. The tool will give you the field magnitude assuming an idealized uniform field between the plates.

What are the units of electric field, and what is the difference between N/C and V/m?

The most common units for electric field are newtons per coulomb (N/C) and volts per meter (V/m). They are actually equivalent: \(1~\text{N/C} = 1~\text{V/m}\). N/C emphasizes the force-per-charge definition \(E = F/q\), while V/m emphasizes the potential-difference-per-distance relationship \(E = V/d\). The Electric Field Calculator lets you pick whichever unit aligns with your problem or textbook convention.

Can the Electric Field Calculator handle multiple charges or non-uniform fields?

The Electric Field Calculator is designed for three canonical cases: a single point charge, an ideal pair of parallel plates, and a uniform field inferred from force on a test charge. For multiple point charges, you can apply superposition manually: compute the field magnitude and direction from each charge at the point of interest, then add the vector contributions. For strongly non-uniform fields, fringing effects, or complex geometries, you typically need numerical methods or specialized field-solving software rather than a closed-form calculator.

Why does my electric field result look unrealistically large or small?

The most common reasons are unit mismatches or unrealistic input combinations. Check that charges are in the correct prefix (μC vs mC vs C), distances are expressed in the right units (mm vs m), and voltage or force values are realistic for your setup. Also confirm that your Result units dropdown matches what you expect; a value that looks tiny in kV/m might be perfectly reasonable when converted back to V/m. If everything checks out, interpret the result in the context of physical limits such as dielectric breakdown and material constraints.

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