Centrifugal Force Calculator

Solve for centrifugal force, mass, or RPM using \(F = m\omega^2 r\) and \(\omega = 2\pi n/60\).

Configuration

Choose what you want to solve for. The calculator will hide that input automatically.

Inputs

Enter the known values. Use radius to the center of mass and steady RPM.

Results Summary

The main result is shown below with supporting quick stats.

Engineering Guide

Centrifugal Force Calculator: How to Use It, What It Means, and When It Matters

This guide explains the equations behind the Centrifugal Force Calculator, how to select the right inputs, and how to interpret results for real rotating systems—from lab centrifuges to flywheels, vehicles, and industrial machinery. You’ll see worked examples, sensitivity tips, and sanity checks so your numbers stay physically realistic.

7–9 min read Updated 2025 Student + Pro Friendly

Quick Start

The Centrifugal Force Calculator is built around the centripetal/centrifugal force relationship for circular motion. In most real applications you know three variables and need the fourth. Follow these steps to avoid the most common mistakes.

  1. 1 Decide what you want to solve for: force \(F\), mass \(m\), or RPM \(n\). The calculator hides the solved row automatically.
  2. 2 Enter the radius \(r\) to the object’s center of mass (not the outer diameter unless the mass is concentrated there).
  3. 3 Enter the rotational speed \(n\) in RPM if it’s known, or leave it blank if you’re solving for it.
  4. 4 Enter the mass \(m\) of the rotating object (or effective mass, if you’re modeling a distributed system).
  5. 5 Choose unit systems that match your data. The calculator converts everything internally to SI, then back to your selected output.
  6. 6 Review the Quick Stats for angular velocity \(\omega\), tangential speed \(v\), and centripetal acceleration \(a_c\). These are your “sanity indicators.”
  7. 7 If results feel high/low, re-check radius and RPM first—those drive the number the most (see below).

Tip: Centrifugal force is often reported as an outward force in a rotating frame, but the math is the same as inward centripetal force in an inertial frame. The calculator computes magnitude only.

Biggest mistake: Using radius to the outer edge instead of radius to the center of mass can overestimate force by 2× or more in thick or distributed objects.

Choosing Your Method

There are a few equivalent ways to compute centrifugal force. Which one is best depends on what measurements you have. Your calculator supports all three by rearranging the same physics.

Method A — RPM Form (most common)

Use this when speed is given in revolutions per minute (motors, centrifuges, rotating shafts). The calculator converts RPM to angular velocity first:

\(\omega = \dfrac{2\pi n}{60}\), then \(F = m\omega^2 r\)
  • Matches how equipment is rated (RPM on nameplates).
  • Best for quick field estimates.
  • Easy to vary speed for “what if” checks.
  • RPM is an average; transient peaks won’t show unless you enter peak RPM.
  • Requires a correct radius to the mass location.

Method B — Angular Velocity Form

Use this if you already have \(\omega\) from simulation, sensors, or control logic (rad/s). This avoids RPM conversion and is common in dynamics or robotics work.

\(F = m\omega^2 r\)
  • No unit conversion step in your workflow.
  • Cleanest for analytical derivations.
  • Less intuitive for many users.
  • Easy to mix degrees/s with rad/s if labels aren’t clear.

Method C — Tangential Speed Form

Use this when you know the linear speed at radius \(r\), such as conveyor drums, rims, or vehicle cornering speed. It uses:

\(F = \dfrac{mv^2}{r}\), where \(v = \omega r\)
  • Natural for systems described by m/s or ft/s.
  • Useful for translating between rotation and linear motion.
  • Requires consistent radius for v and force location.
  • Still sensitive to speed squared.

Internally, the calculator always uses the same core equation and simply rearranges it depending on your Solve For selection.

What Moves the Number the Most

Centrifugal force is extremely sensitive to speed. A small RPM change can create a large force change. Use these “levers” to reason about your results quickly.

Rotational speed \(n\) or \(\omega\)

Force scales with the square of speed: \(F \propto \omega^2\). Doubling RPM increases force by about 4×.

Radius \(r\)

Force increases linearly with radius: \(F \propto r\). If mass distribution shifts outward (e.g., longer arm), force rises proportionally.

Mass \(m\)

Force scales linearly with mass. When modeling distributed systems, use effective mass at the radius of interest.

Center of mass location

For non-point masses (e.g., rods, disks), the radius to the center of mass matters. Using outer radius overestimates force.

Units and conversions

Mixing lbm and lbf, or inches and feet, can silently wreck results. Always confirm your unit selects match your inputs.

Assumptions (steady, rigid, balanced)

The equation assumes steady rotation, rigid links, and negligible imbalance. Real machines may see higher peak loads due to vibration or shock.

Worked Examples

These examples mirror situations engineers commonly Google. Follow the same flow in your calculator, and compare your outputs to the manual math.

Example 1 — Find Centrifugal Force on a Rotating Arm

  • Mass: \(m = 3.0\ \text{kg}\)
  • Radius: \(r = 0.40\ \text{m}\)
  • Speed: \(n = 900\ \text{RPM}\)
  • Solve for: Force \(F\)
1
Convert RPM to angular velocity: \(\omega = \dfrac{2\pi n}{60}\).
2
Compute force: \(F = m\omega^2 r\).

Step 1: RPM to rad/s

\[ \omega = \frac{2\pi(900)}{60} = 94.25\ \text{rad/s} \]

Step 2: Force

\[ F = (3.0)(94.25^2)(0.40) = (3.0)(8883.1)(0.40) \approx 10{,}660\ \text{N} \]

Your calculator should return about \(1.07\times 10^4\ \text{N}\) (or about 2400 lbf). Notice how large the force is compared to the 3 kg weight—speed dominates.

Example 2 — Find Required RPM for a Centrifuge Load

  • Force target: \(F = 500\ \text{N}\)
  • Mass: \(m = 0.25\ \text{kg}\) (250 g sample carrier)
  • Radius: \(r = 0.12\ \text{m}\)
  • Solve for: RPM \(n\)
1
Rearrange for \(\omega\): \(\omega = \sqrt{\dfrac{F}{mr}}\).
2
Convert to RPM: \(n = \dfrac{60\omega}{2\pi}\).

Step 1: Angular velocity needed

\[ \omega = \sqrt{\frac{500}{(0.25)(0.12)}} = \sqrt{\frac{500}{0.03}} = \sqrt{16666.7} = 129.1\ \text{rad/s} \]

Step 2: Convert to RPM

\[ n = \frac{60(129.1)}{2\pi} = \frac{7746}{6.283} \approx 1233\ \text{RPM} \]

The calculator should return roughly 1230 RPM. If you double the force target, RPM only increases by \(\sqrt{2}\) because force scales with speed squared.

Common Layouts & Variations

The same equation shows up across many engineering domains. The table below summarizes common configurations, what radius and mass mean in each, and typical design considerations.

ApplicationWhat \(m\) RepresentsWhat \(r\) RepresentsTypical UsePros / Cons
Lab centrifuge rotorSample + carrier massDistance from spindle to sample COMCompute g-forces or required RPMHigh precision; sensitive to imbalance
Flywheel / energy storageEffective rim massMean radius of mass distributionEstimate rim forces and stressesHuge forces at speed; material limits critical
Rotating machinery (fans, impellers)Blade or tip mass segmentTip radiusBolt and hub loading checksSimple model; ignores fluid dynamic loads
Vehicle cornering / turntableVehicle mass or payloadTurn radius (path radius)Compute lateral force demandsLinear speed form often clearer
Amusement ridesRider + seat massRotation radius to seat COMSafety load checks and comfort limitsMust consider peak transients and restraints

Interpretation tip: If your system has distributed mass, you can approximate by lumping mass at its center of mass radius. For deeper analysis, integrate \(dm\cdot r\cdot \omega^2\) over the geometry.

Specs, Logistics & Sanity Checks

Engineers usually search this calculator to confirm real equipment loads. Here’s what to verify before you trust a number for design or safety decisions.

Geometry & Mass Reality

  • Use radius to center of mass, not to the outer edge by default.
  • For a rod rotating about one end, COM is at \(r=L/2\).
  • For a thin ring, COM is near the ring radius (outer edge is OK).
  • Include fixtures, carriers, or fasteners if they rotate with the mass.

Speed Reality

  • Enter peak RPM if evaluating maximum load.
  • Check nameplate vs. controller limits for overspeed.
  • Acceleration ramps can momentarily exceed steady-state loads.
  • For variable-speed systems, evaluate the worst-case operating point.

Structural & Safety Checks

  • Compare \(a_c\) to gravity: \(g \approx 9.81\ \text{m/s}^2\).
  • Stresses usually scale with force; apply appropriate safety factors.
  • Consider imbalance loads—real rotors rarely stay perfectly centered.
  • If forces exceed fastener or material limits, redesign before testing.

Finally, ask: “Does the result make physical sense?” If your computed force is orders of magnitude above a component’s rated load, you either found a real hazard or you entered the wrong radius/speed.

Safety note: High rotational forces can cause catastrophic failures. Never spin test a rotor above rated speed without containment and manufacturer guidance.

Frequently Asked Questions

Is centrifugal force “real” or just a fictitious force?
In an inertial frame, the real interaction is the inward centripetal force that keeps an object on a circular path. In a rotating frame, you can model the same effect as an outward centrifugal force. The calculator gives the magnitude either way: \(F = m\omega^2 r\).
What radius should I use for a distributed object?
Use the radius to the object’s center of mass. For a uniform rod rotating about one end, that’s \(r=L/2\). For a uniform disk about its center, the COM is at the axis so this formula applies to any specific mass element; use a rim-mass approximation for quick checks.
Why does the force increase so fast with RPM?
Because speed is squared. Since \(\omega = 2\pi n/60\), doubling RPM doubles \(\omega\), and \(F \propto \omega^2\) makes force roughly 4× larger.
Can I use this calculator for vehicle turning or cornering?
Yes. That case is usually easier in linear form: \[ F = \frac{mv^2}{r} \] where \(v\) is vehicle speed and \(r\) is turn radius. It’s the same physics.
What’s the difference between lbm and lbf in this context?
lbm is mass, lbf is force. The calculator converts mass to kilograms internally. If you enter force in lbf, it converts to Newtons before computing. Don’t interchange them.
How do I estimate “g-forces” from the output?
Use centripetal acceleration: \[ a_c = \omega^2 r \] Then divide by \(g\approx 9.81\ \text{m/s}^2\). For example, \(a_c=98.1\ \text{m/s}^2\) is about 10 g.
Does imbalance change the force predicted here?
Yes. The equation assumes perfectly balanced rotation. Any eccentricity adds dynamic loads, often at multiples of the steady centrifugal force. Use this calculator for baseline magnitude, then apply vibration/imbalance analysis for final design.
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